Question

the diagonal of square is 42.3 cm long. find the length of its side and area of square.

Answer 1

let the side of the square be x.
therefore, by pythagoras theorem,
$x^{2}+ x^{2} = (42.3)^2$
this implies that, [tex]2 x^{2} = 1789.29 x^{2} =894.645 x=29.91 (approx.) [/tex]

Answer 2

DIAGONAL=SQUARE ROOT OF 2*SIDE
42.3/1.41=SIDE=3.096CM
AREA=3.096*3.096
          =9.44CM