Math, asked by ushamahar7111, 11 months ago

The diagonal of the rectangle is 15cm if the length of the rectangle is 12cm what will be the peremeter of this rectangle

Answers

Answered by Anonymous
8

ANSWER :

Perimeter of rectangle is 42 cm.

EXPLANATION :

Given :-

  • Diagonal of rectangle=15 cm.
  • Length of rectangle = 12 cm.

To find :-

  • Perimeter of the rectangle.

Solution :-

Diagonal = 15 cm.

Length = 12 cm.

Let the breadth of the rectangle be x cm.

We know,

Diagonal of rectangle=√(Length²+Breadth²)

Diagonal=√(Length²+Breadth²)

→15=√(12²+x²)

→15²=12²+x²

→225=144+x²

→225-144=x²

→81=x²

→√81=x

→9=x

Breadth = 9 cm.

★Now find the perimeter of the rectangle.

We know,

Perimeter of rectangle=2(l+b)

Perimeter of rectangle=2(l+b)

Perimeter of rectangle=2(12+9)cm

Perimeter of rectangle= 42 cm.

______________________________

Answered by silentlover45
0

  \huge \mathfrak{Answer:-}

\implies 42.

\large\underline\mathrm{Given:-}

  • Diagonal of rectangle = 18cm.
  • height of rectangle = 12cm.

\large\underline\mathrm{To \: find}

  • perimeter of the rectangle.

\large\underline\mathrm{Solution}

  • Let the breadth of the rectangle be x cm.

\large\underline\mathrm{Diagonal \: of \: rectangle \: = \: √l² \: +\:  b²}

\implies 15 = √12² + x²

\implies 15² = 12² + x²

\implies 225 = 144 + x²

\implies 81 = x²

\implies x = 9

\impliesBreadth = 9cm

perimeter of the rectangle = 2(l + b)

\implies 2(12 + 9)

\implies 2 × 21

\implies 42.

\large\underline\mathrm{hence,}

\large\underline\mathrm{the \: perimeter \: of \: the \: rectangle \: is \: 42cm.}

\large\underline\mathrm{Hope \: it \: helps \: you \: plz \: mark \: me \: brainlist}

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