The diagonals AC and BD intersect at O in a rectangle ABCD. If angle AOD = 45 degrees, find
angle DAC
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The diagonal of a rectangle are equal and bisect each other which => OA = OD => angle OAD = angle ODA = x (let)
Now in triangle OAD
Angle A + angle O + angle D = 180 => x+ x + 45 = 180 => 2x = 180-45=> x = 135/2=> 67.5 => angle DAC = 67.5
jithinbj:
The diagonal of a rectangle are equal and bisect each other which => OA = OD => angle OAD = angle ODA = x (let) Now in triangle OAD Angle A + angle O + angle D = 180 => x+ x + 45 = 180 => 2x = 180-45=> x = 135/2=> 67.5 => angle DAC = 67.5
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In a rectangle the diagonals bisect each other. Hence the triangle OAD is an Isosceles triangle.
Hence, angle DAC + angle ADO + angle AOD = 180
as angle DAC = angle ADO ,
angle DAC = angle ADO = (180 - 45) / 2 = 67.5 degrees
Hence, angle DAC + angle ADO + angle AOD = 180
as angle DAC = angle ADO ,
angle DAC = angle ADO = (180 - 45) / 2 = 67.5 degrees
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