The diagonals AC and BD of a parallelopram ABCD intersect each other at a point O.
DAC = 30°, AOB = 70° then ADO = ?
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Answer:
ADO=40
AOD+AOB=180
AOD+70=180
AOD=180-70=110
IN triangle AOD
AOD+DAO+ADO=180
110+30+ADO=180
ADO=180-140=40
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