Question

The diagonals AC and BD of parallelogram ABCD intersect at the point o. If __DAC = 34 and ZAOB= 75 then
measure _DBC is
340
1750
​

Answer 1

Answer:

∠DBC = 41°

Step-by-step explanation:

ABCD is a parallelogram .

∴ AD | | BC ⇒ ∠ACB = ∠DAC = 34°

Now, ∠AOB is an exterior angle of △BOC

∴ ∠OBC + OCB = ∠AOB [ ext ∠ = sum of two int. opp. ∠S]

⇒ ∠OBC + 34° = 75°

⇒ ∠OBC = 75° - 34° = 41°

or ∠DBC = 41°