The diagonals of 2 squates are in the ratio of 3:5 then their areas wil be
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the ratio of their area =9:25
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let the diagonals are 3x and 5x
and side of first square is y and side of second square is z then
using Pythagoras theorm we get
y^2 + y^2= 9x^2
2 y^2 = 9 x^2
and
z^2+ z^2 = 25 x^2
2z^2a= 25 x^2
y^2 : z^2
(9/2)x^2 : (25/2)x^ 2
9:25
and side of first square is y and side of second square is z then
using Pythagoras theorm we get
y^2 + y^2= 9x^2
2 y^2 = 9 x^2
and
z^2+ z^2 = 25 x^2
2z^2a= 25 x^2
y^2 : z^2
(9/2)x^2 : (25/2)x^ 2
9:25
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