The diagonals of a parallelogram ABCD intersect at point O. If angle BOC = 90 degree and angle BDC = 50 degree, then ∠ BAC is
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Answer:
40 °
Step-by-step explanation:
If Angle BOC is 90 then all other angles at O become 90 (liners pairs and vertically opposite angle) anlge BDC is angle DBA (alternate angles)
In TRIANGLE ABO,,,
AOB plus ABO plus BAO equal to 180
which gives BAO or BAC as 40
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