Question

The diagonals of a parallelogram ABCD intersect of O. If ZBOC = 80º and ZACB = 300.
then find ZODA.​

Answer 1

Answer:

In given figure,

Quadrilateral ABCD is a parallelogram.

So, AD ∣∣ BC

∴ ∠DAC = ∠ACB  --- ( Alternate angle)

∴ ∠ACB = 32  

∘

 

∠AOB + ∠BOC = 180  

∘

  --- (straight angle)

⇒70  

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 + ∠BOC = 180  

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∴ ∠BOC = 110  

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In △BOC,

∠OBC + ∠BOC + ∠OCB = 180  

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⇒∠OBC  + 110  

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 + 32  

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 = 180  

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⇒ ∠OBC = 38  

∘

 

∴  ∠DBC = 38  

∘

Step-by-step explanation: