Math, asked by tpp292003, 10 months ago

The diagonals of a parallelogram are 3i – 4j – k and 2i + 3j – 6k. Show that the parallelogram is a rhombus

Answers

Answered by ravi8682

0

Answer:

taking dot product

(3i-4j-k).(2i+3j-6k)

= 6-12+6

=0

hence diagonals are perpendicular to each other

and the parallelogram with diagonals intersecting at right angle is rhombus

hope this will help you

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