the diagonals of a parallelogram are equal then show that it is a rectangular
Answers
Given :-
A parallelogram ABCD in which the diagonals are equal i.e. AC = BD
To Prove :-
ABCD is a rectangle.
Proof :-
In ∆ ABC and ∆ ADC ,
- AB = DC ( Opposite sides of a parallelogram are equal )
- AC = BD ( Given )
- AC = CA ( Common )
Therefore, by SSS criterion for congruence ∆ ABC and ∆ ADC are congruent.
Therefore,
- angle ABC = angle DCB ( by CPCT ) { Statement 1 }
Now, since ABCD is a parallelogram,
Therefore, AB II DC ( Since, opposite sides of a parallelogram are parallel )
So, let CB be a transversal. Now,
( Since the angles on the same side of the transversal add up to 180°
And according to statement 1, angle B and angle C are equal. Therefore,
Therefore the value of one of the angles is 90 and we know that the opposite angles of a parallelogram are equal. Hence, all the angles measure 90°.
Therefore, ABCD is a rectangle.
Hence, proved.
Know More :-
There are some criterions for congruency of two triangles. They are as follows :-
- SSS criterion
- SAS criterion
- ASA criterion
- RHS criterion
1. SSS CRITERION :- ( side-side-side )
This criterion states that if two triangles have same measure of corresponding sides then they are congruent.
2. SAS CRITERION :- ( side - angle - side )
This criterion states that if two triangles have two corresponding sides and the including angle with equal measures then they are said to be congruent.
3. ASA CRITERION :- ( angle- side - angle )
This criterion states that if two triangles have two corresponding angles and including side equal then they are said to be congruent.
4. RHS CRITERION :- ( right angle - hypotenuse - side )
This criterion states that if the corresponding hypotenuse and side of two triangles measure same then the triangle is said to be congruent.