Question

The diagonals of a parallelogram PQRS are along the lines

x + 3y = 4 and 6x - 2y = 7.

Then, PQRS must be a

(a) rectangle

(b) square

(c) cyclic quadrilateral

(d) rhombus

✔️✔️Proper solution needed ✔️✔️​

Answer 1

diagonals are perpendicular to each other
so,pqrs will either be square or rhombus

Answer 2

The slope of x +3y = 4 is 1/3 And 6x -2y = 7 is -3 So the product of the slope is 1/3 *(-3) = -1 Hence the diagonals are perpendicular to each other.

Here the answer option can be rhombus as well as square.