the diagonals of a rectangle ABCD intersect at O if angle BOC is equal to 60 degree find angle ODA
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4
Answer:
AOD=BOC =60⁰( vertically opposite angles)
since diagonal of rectangle bisects the angle therefore OAD=45⁰(90⁰/2)
Then using angle sum property, ODA=180⁰-(45⁰+60⁰)
=180⁰-105⁰
=75⁰
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Answer:
In triangle BOC,
ang BOC +ang OCB+ang OBC= 180°
60°+2 ang OBC= 180° [as triangle OBC is an isocelestriangle, the base angles are equal]
2 ang OBC=180°-60°
=120°
ang OBC=128/2 °
ang OBC=60°
ang OBC=ang ODA
ang ODA=60°
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