Question

the diagonals of a rectangle ABCD intersect at O. if angle AOB=114 degree ,find angle ACD and angle ADB
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Answer 1

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Answer 2

Step-by-step explanation:

we know that, Diagonal of rectangle are equal and bisect to each other

AC=DB

½AC=½DB

AO=BO

ang OAB=OBA

In triangle AOB

Let ang OAB=OBA=x

x+114+x=180°

or 2x=180-114

or 2x=66

x=66/2

x=33

we know that opposite side of rectangle are parallel to each other

ang OAB= ang ACD. (alternate angle)

ACD=33

BOC=180-114=66°

ACB=90-33=57

CBO=180-66+57

CBO=180-123

CBO=57

AB Parallel DC

CBO= ADB=57° ans