Question

The diagonals of a rectangle ABCD intersect at O. If angle BOC = 44°, find angle OAD

Answer 1

Heya mate, Here is ur answer

Angle DOA=angle BOC(vertically opposite angles)

Angle DOA=44°

We know that in a rhombus diagonals are equal and bisect each other.

So, AC=BD

$\frac{ac}{2} = \frac{bd}{2}$

AO=OD(diagonals bisect each other in a rectangle)

So, angle OAD=angle ODA(angles opposite to equal sides are equal)

So, ∆AOD is an isosceles ∆ .

Using angle sum property in ∆AOD

angle DOA+angle ODA+angle OAD=180°

44°+angle OAD+angle OAD =180°

44°+2×angle OAD=180°

2×angle OAD=180°-44°

2×angle OAD=136

angle OAD=136/2

angle OAD=68°

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@Laughterqueen

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Answer 2

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