Question

The diagonals of a rectangle are 2x + 1 and 3x – 1, respectively. Find the value of x.
1 point
A. 1
B. 2
C. 3
D. 4

Answer 1

Answer:

2x+1=3x-1

3x-1-2x-1=0

x-2=0

x=2

Answer 2

Answer: 2

Step-by-step explanation:

❍ Given :-

• Diagonals of rectangle are 2x + 1 and 3x - 1

❍ To Find :-

• The value of x

❍ Solution :-

The diagonals of a rectangle are equal.

Hence, 2x + 1 = 3x - 1

➸ 2x + 1 - (3x - 1) = 0

➸ 2x + 1 - 3x + 1 = 0

➸ - x + 2 = 0

➸ - x = - 2

➸ $\sf \fbox{x = 2}$

❍ Verification :-

⇝ Putting x = 2 in eq. 2x + 1

➸ 2(2) + 1

➸ 4 + 1 = 5

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬

⇝ Putting x = 2 in eq. 3x - 1

➸ 3(2) - 1

➸ 6 - 1 = 5

Both equation resultant are same hence the value is correct.

Option (B) 2 is the right answer.