The diagonals of a rhombus ABCD are 10 cm and 8 cm. What
would be its area and length of a side.
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Area of the rhombus = 1/2 * d1 * d2
= 1/2 * 10 * 8
= 40cm^2
= 1/2 * 10 * 8
= 40cm^2
melwinjo:
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Answered by
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area=(1/2)d1×d2
area=(1/2)×8×10=40
as rhombus form 4 right angle triangle
l^2=4^2+5^2
l=√41
area=(1/2)×8×10=40
as rhombus form 4 right angle triangle
l^2=4^2+5^2
l=√41
thanks a lot
please keep my answer as brainliest
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