Question

the diagonals of a rhombus are 12cm ,16cm.Find the length of one side of the rhombus

Answer 1

Answer is 20 solve it by pyathagoras theorem

Answer 2

We know that the diagonals of a rhombus bisect at right angles.

Let ABCD be the rhombus and AC and BD bisect at O.

AO =
$\frac{16}{2} = 8 \: cm$

BO =
$\frac{12}{2} = 6\: cm$

In right triangle ABO,
AB^2=AO^2+BO^2
$= {6}^{2} + {8}^{2}$
$= 36 + 64$
$= 100$

AB =
$\sqrt{100}$
$= 10 \: cm$

Thanks :)