the diagonals of a rhombus are 12cm and 16cm find the area and the length of the sides of the rhombus
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1
In a Rhombus ABCD
Diagonals intersect at O
AC=12cm
BD=16cm
area of rhombus is 1/2(products of diagonals)
therefore area of rhombus is 1/2(12*16)==96cm^2
NOW
half of AC=AO
half of 12cm=A0
AO=6cm
half of BD=OD
half of 16cm=OD
OD=8cm
AD=side of rhombus ABCD
side2=AO2 + OD2 (pytha. theorum)
side2=62 + 82
side2=36 + 64
side2=100
side2=102
side=10cm
Diagonals intersect at O
AC=12cm
BD=16cm
area of rhombus is 1/2(products of diagonals)
therefore area of rhombus is 1/2(12*16)==96cm^2
NOW
half of AC=AO
half of 12cm=A0
AO=6cm
half of BD=OD
half of 16cm=OD
OD=8cm
AD=side of rhombus ABCD
side2=AO2 + OD2 (pytha. theorum)
side2=62 + 82
side2=36 + 64
side2=100
side2=102
side=10cm
Answered by
2
area of rhombus= 1/2 d1× d2
=12×16÷2
=96 square cm
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