Question

the diagonals of a rhombus are 12cm and 6cm find the length of one side of the rhombus also find the perimeter of the rhombus

Answer 1

Let a rhombus ABCD
Diagonal AB =12 cm
BD=6cm
We know that diagonal of a rhombus are perpendicular bisectors of each other.
Therefore, In right triangle A to B
OB=
$\frac{1}{2} \times 6 = 3$
OA=
$\frac{1}{2} \times 12 = 6$
According to Pythagoras property
$(ab) {}^{2} = (oa) {}^{2} + (ob) {}^{2}$
(AB)square=(3)sq. +(6)sq.
ABsq.=3×3+6×6
ABsq.=9+36
ABsq.=45
ABsq.=
$\sqrt{45}$
All sides of rhombus are equal to each other=
AB=BC=CD=
$\sqrt{45}$
Sorry but next I don't know
Hope the rest helps u