Question

The diagonals of a rhombus are 16 cm and 12 cm find the length of each side of the Rhombus

Answer 1

diagonals of a rhombus are perpendicular bisectors of each other

thus by Pythagorean theorem
${(\frac{1}{2} \times 16)}^{2} + {( \frac{1}{2} \times 12) }^{2} = {side }^{2} \\ \\ {8}^{2} + {6}^{2} = {side }^{2} \\ \\ 64 + 36 = {side }^{2} \\ 100 = {side}^{2} \\ \\ side = 10 \: cm$