Math, asked by navyarajiv, 1 year ago

the diagonals of a rhombus are 24cm and 10cm. Find its area and perimeter.
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Answers

Answered by siddhartharao77
208
Area = 1/2 * 24 * 10

         = 120 cm^2.

Perimeter s^2 = (24/2)^2 + (10/2)^2
 
                        =  12^2 + 5^2

                       =   169

                   s = 13.

The perimeter of the rhombus = 4 * 13 = 52cm.

mysticd: perimeter s² is wrong sir , plz , edit
siddhartharao77: Thanks Bro..
navyarajiv: thanks
Answered by mysticd
185
Hi ,

Let d1 , d2 are diagonals of the Rhombus ,

d1 = 24cm

d2 = 10 cm

area = ( d1 d2 ) / 2

A = ( 24 × 10 ) / 2

A = 120 square cm

Let side if the Rhombus = a cm

a² = ( d1/2 )² + ( d2/2 )²

= ( 24 / 2 )² + ( 10 /2 )²

= ( 12 )² + 5²

= 144 + 25

= 169

a = √169

a = 13 cm

perimeter of the Rhombus = 4a

P = 4 × 13

P = 52 cm

I hope this helps you.

:)

navyarajiv: thanks
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