the diagonals of a rhombus are 24cm and 10cm. Find its area and perimeter.
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Answered by
208
Area = 1/2 * 24 * 10
= 120 cm^2.
Perimeter s^2 = (24/2)^2 + (10/2)^2
= 12^2 + 5^2
= 169
s = 13.
The perimeter of the rhombus = 4 * 13 = 52cm.
= 120 cm^2.
Perimeter s^2 = (24/2)^2 + (10/2)^2
= 12^2 + 5^2
= 169
s = 13.
The perimeter of the rhombus = 4 * 13 = 52cm.
mysticd:
perimeter s² is wrong sir , plz , edit
Answered by
185
Hi ,
Let d1 , d2 are diagonals of the Rhombus ,
d1 = 24cm
d2 = 10 cm
area = ( d1 d2 ) / 2
A = ( 24 × 10 ) / 2
A = 120 square cm
Let side if the Rhombus = a cm
a² = ( d1/2 )² + ( d2/2 )²
= ( 24 / 2 )² + ( 10 /2 )²
= ( 12 )² + 5²
= 144 + 25
= 169
a = √169
a = 13 cm
perimeter of the Rhombus = 4a
P = 4 × 13
P = 52 cm
I hope this helps you.
:)
Let d1 , d2 are diagonals of the Rhombus ,
d1 = 24cm
d2 = 10 cm
area = ( d1 d2 ) / 2
A = ( 24 × 10 ) / 2
A = 120 square cm
Let side if the Rhombus = a cm
a² = ( d1/2 )² + ( d2/2 )²
= ( 24 / 2 )² + ( 10 /2 )²
= ( 12 )² + 5²
= 144 + 25
= 169
a = √169
a = 13 cm
perimeter of the Rhombus = 4a
P = 4 × 13
P = 52 cm
I hope this helps you.
:)
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