The diagonals of a rhombus are 30 cm and 16 cm. Find the length of a side of the rhombus.
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4
The diagonals of rhombus bisects each other at 90⁰
If ABCD is a rhombus then
AC=16
BD=30
They bisects each other at point o then
AO=OC=8
BO=OD=15
By Pythagoras theorem (AB)²=(AO)²+(BO)²
(ΑΒ)²=15²+8²=225+64=289
AB=17
If ABCD is a rhombus then
AC=16
BD=30
They bisects each other at point o then
AO=OC=8
BO=OD=15
By Pythagoras theorem (AB)²=(AO)²+(BO)²
(ΑΒ)²=15²+8²=225+64=289
AB=17
Answered by
3
Answer:
diagonals, d1 and d2, of a rhombus are given then each side = [(d1/2)^2+(d2/2)^2]^0.5.
Step-by-step explanation:
Example: d1 = 12 cm, d2 = 16 cm
Side, s = [(12/2)^2+(16/2)^2]^0.5 = [6^2+8^2]^0.5 = [36+64]^0.5 = 100^0.5 = 10 cm.
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