Question

the diagonals of a rhombus are in the ration 5:12 if it's perimeter is 104 cm find the lengths of the sides and the diagonals​

Answer 1

plze marknme as brailiesttt plze dearRombus all 4 side are equal

X+x+x+x = 104

4x= 104

X= 26 cm

Now diagonals of rombus bisect each other at 90 then

26² = (5x)²+(12x)²

676 = 25x² + 144x²

676 = 169x²

X² = 676/169

X²= 4

X = 2

Hence 5*2 = 10 and 12*2= 24 …Hence full length of diagonals are 10+10 = 20 and 24+24=48