the diagonals of a rhombus is 16 cm and 30 cm . find its perimeter
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Its perimeter is 64cm
TheDk:
It's 68 cm
but acc. to me ,perimeter is equal to sum of all sides and one side is given and rhombus property is all sides are equal so ,16+16+16+16 =64
You've misunderstood! The questions says the diagonals are 16 and 30 cm. They're diagonals
someone has given clear explanation of the method to be done
ok ok
Answered by
4
the diagonals of the rhombus is 16cm and 30cm.
if (1/2 *16) and (1/2* 30)
then
the daigonal is 8cm and 15cm
by pythogorus therium
(a)^2 + (b)^2 = (c)^2
(8)^2 + (15)^2 = (c)^2
64+225 = (c) ^2
289 = (c) ^2
c = 17
the perimeter is (4 * sides)
( 4 *17 )
68 cm
if (1/2 *16) and (1/2* 30)
then
the daigonal is 8cm and 15cm
by pythogorus therium
(a)^2 + (b)^2 = (c)^2
(8)^2 + (15)^2 = (c)^2
64+225 = (c) ^2
289 = (c) ^2
c = 17
the perimeter is (4 * sides)
( 4 *17 )
68 cm
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