The diagonals of a rhombus measure 16 cm and 30 cm. Find its perimeter.
[Hint : Diagonals of a rhombus bisect each other at right angles.]
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Given: Diagonals AC=30cm and DB=16cm.
Since the diagonals of the rhombus bisect at right angle to each other.
Therefore, OD= DB /2 = 16/2 = 8 cm
and OC= AC/ 2 = 30/2 = 15
Now, In right angle triangle DOC,
(DC)2 =(OD) 2 +(CO) 2
= (8) 2+ (15)2
=64+225=289
DC = 17 cm
Perimeter of the rhombus=4× side
=4×17=68cm
Thus, the perimeter of rhombus is 68 cm
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