Question

the diagonals of a rhombus measure 16 cm and 30 cm  .find its perimeter    ( in easy way)? For std 7th

Answer 1

In this question, It is given that,

$D_{1}= 16 cm \\D_{2} = 30 cm$

When two half Diagonal of Rhombus meet at a point then they incloses a Δ.

So, Using Pythagoras theorem to Find its side.

⇒ $\frac{16}{2} = 8 cm \\\frac{30}{2} = 15 cm$

Now,

As we know about Pythaogras theorem, Let 'a' as the side of Rhombus

⇒ a²= p²+b²

⇒ a²= (15²+8²) cm²

⇒ a²= 289cm²

⇒ a = √289 cm²

⇒ a = 17 cm

Now,

Perimeter of Rhombus = 4 x side = 4 x a = 4 x 17 cm = 68 cm

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