Question

The diagonals of a rhombus measure 16cm and 30cm. Find its perimeter.​

Answer 1

Answer:

perimeter of a rhombus =p

p=4a

p=4*√p^2+q^2 / 2

p=2*√16^2+30^2

p=68

Step-by-step explanation:

here p and q are diagonals

Answer 2

Answer:

When diagonal is given

Perimeter = 2squre root( D1^2+ D2^2)

D1 = diagonal 1

D2 = diagonal 2

P = 2 squreroot( 16^2 + 30^2)

P = 2 squre root ( 256+ 900)

P = 2 squre root( 1156)

P = 2× 34

P = 68

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Step-by-step explanation:

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