Question

The diagonals of a rhombus measure 8 cm and 6 cm . Find its perimeter

Answer 1

Answer:

Step-by-step explanation:  Diagonal d1 = 8cm = 8/2 = 4cm.

Diagonal d2 = 6cm = 6/2 = 3cm.

By Pythagoras theorem.

AC^2 + AB^2 = BC^2

D1^2 + D2^2 = S^2

4^2 + 3^2 = S^2

16 + 9 = S^2

25 = S^2

S = 5cm.

We know that perimeter = 4 * S

                                        = 4 * 5

                                        = 20cm.

hope this helps you