Question

The diagonals of a square ABCD intersect at a point O. Show that ∆AOB =~∆COD

Answer 1

In triangle AOB and triangle COD,
-angle AOB = angle COD (vertically opposite angles.)
-AO = CO ( diagonals bisect each other of a square)
-DO = BO (diagonals bisect)
therefore,
triangle AOB ~= triangle COD ( SAS rule) proved...
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