Question

The diagonals of rectangle ABCD cut at K.
If LAKB = 110°, then ZACB and ZACD
are :​

Answer 1

Answer:

by the way if u want to show any angle in a quadrilateral then u can use only three letters .

Answer 2

DKC=AKB(VERTI.OPP.ANG.A.EQ.)

=110°

KC=KD(DIAGONALS ARE EQUAL AND BISECT EACH OTHER)

DCK=CDK(EQUAL SIDES HAVE EQUAL S OPPOSITE TO THEM )

BUT

DKC+DCK+CDK=180°

110°+2DCK=180°

2DCK=70°

DCK=35 =ACD

ACB=90 -35= 55°

now the ans is 35° and 55°