Question

The diagram ADCB is a kite A(3;5) B(-1; -4)=DC and AB=BC ;D is a point such that AD is parallel to the x axis AD=5 units ; CD is perpendicular to the axis the diagonal intersect at P 1, show that the coordinates of c are( 8;0) 2, write down the coordinates of point P 3, calculate the gradient BD. 4,calculate the length AC. 5,calculate the area of kite ADCB.

Answer 1

Answer:

Step-by-step explanation:

Suppose a line makes an angle A with X axis. Then A is known as angle of inclination of the line

Its slope = tan A

1. Since the side AB Parallel to X axis

its angle of inclination with x axis is 0 degree

Slope of AB = tan (0) = 0

2.Since the side BC perpendicular to X axis its angle of inclination with X axis is 90 degrees

Slope of BC = tan (90) = infinite

3. Since the diagonal AC makes an angle 45 degrees with X axis

Slope of AC = tan (45) = 1

I hope this answer helps you