Question

The diagram below shows a uniform bar supported at the middle point ‘O’. A weight of 40gf is placed at a distance 40 cm to the left of the point ‘O’. How can you balance the bar with the weight of 80gf.

Plzz answer ASAP.

Answer 1

We use the rule related to the moments of force :    or torque:

  which is  force (or weight)  multiplied by  the arm length from the pivot,  in this case , that is  the middle point  "O".

Place 80gf to the right of  O on the bar at a distance "X".  Then

         80gf * X = 40 gf * 40 cm

 

so  X = 20 cm.   place the 80gf at 20 cm to the right of o.

Answer 2

Answer:

hope it helps u well

Explanation:

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