Physics, asked by rohan309561, 9 months ago


The diagram below shows the change of phases of a substance on a temperature
vs time graph on heating the substance at a constant rate.
temp. °C
LB
C
time(s)
(i) Why is the slope of CD less than slope of AB?
(ii) What is the boiling and melting point of the substance?​

Answers

Answered by nidaeamann
7

Explanation:

As per question statement there is no graph or table attached. However to answer the question, a reference image is attached.

As we can see in the image, the slope of AB and CD is same, that is gradient value is similar, but the length of CD is more than AB. It is because more energy is required from converting liquid to gas than from solid to liquid.

As far as the melting and boiling points are concerned,  t1 is the melting point while t3 is the boiling point  

Attachments:
Answered by StormBringer
1

Answer:

i) The slope of CD is less than slope of AB as specific heat capacity of liquid phase of same material can be different from that of solid phase of same material.

ii) The melting point is t1 while the boiling point is t2.

Explanation:

Hope it helps!

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