Question

The diagram in Fig. 1.29 shows two forces F, = 5and F, = 3 N acting at points A and B of a rod pivotedat a point o, such that OA = 2 m and OB = 4 m.
F1=5N and F2 = 3N acting at points A andB of a rod pivoted at a point O
Calculate :
(i) the moment of force F1 about 0.
(ii) the moment of force F2 about O.
(iii) total moment of the two forces about O.
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Answer 1

Answer:

Explanation:

Given:-

F1=5N

D1=2m

F2=3N

D2=4m

(i) we know that

Torque1= Force × perpendicular distance

=Torque1= 5×2=10Nm

(ii) we know that

Torque2=Force×Perpendicular Distance

=Torque2=3×4

=Torque= 12Nm

(iii) We know that

Total moment of force= Torque1-Torque2

Total moment of force = 10-12= -2Nm

Answer 2

Answer:

hope it will help you.....