Question

The diagram represents a solid block of wood. The faces ABCD, APSD, PQRS, BCRQ are rectangular. ABQP
and CDSR are trapeziums.
Given that AB = DC = 7 cm, AP = DS = 8 cm, PQ = SR = 13 cm and QR = PS = 40 cm, calculate:
(a) the area of ABQP,
(b) the volume of the block of wood,​

Answer 1

Answer:

Area of ABPQ = 80cm² and the volume of woodblock = 3200cm³

Given:

AB = DC = 7 cm, AP = DS = 8 cm, PQ = SR = 13 cm and QR = PS = 40 cm,

To find:

(a) the area of ABQP,

(b) the volume of the block of wood,

Solution:

(a.) Area of ABQP = 1/2 *(a+b)*h

                       = 1/2 * (7+13) *8

                       = 80 cm²

(b.) Volume = Area of ABPQ * h

                = 80cm² * 40cm

                 =  3200 cm³

Hence, the Area of ABPQ is 80cm² and the volume of the wood block is 3200cm³