Question

The diagram shows a heater coil and a resistor connected to a 12 V battery and an ammeter. The ammeter reading is 1.2 A. pls help me on this question

Answer 1

Answer:

i) V=IR (Ohm's Law)

where V is voltage, I is current, R is resistance

ii) V=12

I= 1.2 A

R= 4 ohms

V'=IR

  = 1.2*4

   = 4.8 V

iii)Vh+V' = V

 =Vh+4.8=12

 =Vh= 12-4.8

 =Vh=7.2 V

iv) t= 5 mins = 300 s

E= VhIt

   =7.2*1.2*300

   = 2592 J