Math, asked by tamoremayank, 1 day ago

The diagram shows a rectangle PQRS. T lies on PQ such that ZPST = 28º and ZSRT = 43°​

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Answered by changlydia24
0

Answer:

Given ,

PQRS is a rectangle

angle PST = 28⁰

Angle SRT = 43⁰

Since PQRS is a rectangle , the angle of each corner is 90⁰ so

angle PSR = SRQ = RQP = QPS = 90⁰

1) lets take triangle SPT ,

sum of all angles of triangle SPT = 180⁰

angle PST + angle PTS+ angle SPT= 180⁰

28 + angle PTS +90 = 180⁰

Angle PTS = 180 - 118

Angle PTS = 62 ⁰

2) Now let's take triangle SRT,

Sum of all angles of triangle SRT = 180

Angle TSR + angle SRT + angle RTS = 180⁰

62 + 43 + angle RTS = 180⁰

angle RTS = 180 - 105

angle RTS = 75⁰

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