The diagram shows the variation of air pressure from an alarm siren at particular instant. The speed of sound in air is 340 m/s. What is the period of the alarm siren?
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Given that the 340 m/s and you have to find out the time period of the alarm siren? the distance between the two consecutive crests or troughs is lamda. Here lamda + lamda/4 = 1. Therefore, 5lamda/4 = 1, lamda = 4/5 = 0.8 m , T = 0.8/340 = 2.235 ms. Hope the student can get best answer on reading it and it is more helpful.
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