Math, asked by ABSiddique, 11 months ago

the diameter if a sphere is decreased by 25%. By what per cent does decrease in it's C.S.A decrease?​

Answers

Answered by powersteel3344
2

Answer:

If we reduce the diameter by 25%, the radius will also be reduced by 25%.

let initial radius of sphere = r

initial CSA = 4πr²

after reducing it 25%,

25% of r = (25/100)×r = 0.25r

final radius = r - 0.25r = 0.75r

final CSA = 4π(0.75r²) = 4πr²×(0.5625)

decrease in CSA = initial CSA - final CSA = 4πr² -  4πr² × (0.5625)

⇒decrease in CSA = 4πr² × (1-0.5625) = 4πr² × 0.4375

% decrease in CSA = 

Thus CSA decreases by 43.75%.

Answered by harsh188singh
0

Answer:as we know that formula is 4TTr3

So4×22/7×1/25 3

It will increase by 50%

Step-by-step explanation:

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