the diameter if a sphere is decreased by 25%. By what per cent does decrease in it's C.S.A decrease?
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Answered by
2
Answer:
If we reduce the diameter by 25%, the radius will also be reduced by 25%.
let initial radius of sphere = r
initial CSA = 4πr²
after reducing it 25%,
25% of r = (25/100)×r = 0.25r
final radius = r - 0.25r = 0.75r
final CSA = 4π(0.75r²) = 4πr²×(0.5625)
decrease in CSA = initial CSA - final CSA = 4πr² - 4πr² × (0.5625)
⇒decrease in CSA = 4πr² × (1-0.5625) = 4πr² × 0.4375
% decrease in CSA =
Thus CSA decreases by 43.75%.
Answered by
0
Answer:as we know that formula is 4TTr3
So4×22/7×1/25 3
It will increase by 50%
Step-by-step explanation:
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