The Diameter of 125 cm long roller is 84 cm. If it takes 500 complete revolutions to level a playground, find the cost of levelling at 75 paise per square metre.
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surface area of cylindrical roller=2.pi.r.h
=2 x 22/7 x 84 x 125
=66000 cm^2
now ,
total area levelling by roller =no of revolution by roller x surface area of roller
=500 x 66000/10000 m^2=3300m^2
hence cost of levelling by roller=75/100 x3300=75 x 33 =2475 Rs
=2 x 22/7 x 84 x 125
=66000 cm^2
now ,
total area levelling by roller =no of revolution by roller x surface area of roller
=500 x 66000/10000 m^2=3300m^2
hence cost of levelling by roller=75/100 x3300=75 x 33 =2475 Rs
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