The diameter of a 120cm long roller is 98cm. If it takes 1000 complete revolutions to level a playground. Find the area of the playground in sq.m.
Answers
Answered by
1
3696 sq.m. will be the area of the playground
sreelover:
can u tell me why r we multiplying 1/100 twice?
Actually 1m^2 = 10000 sqcm.(100 * 100)
Answered by
6
Given Diameter of the roller d = 98cm.
Then the radius of the roller r = 98/2
= 49cm.
We know that Area of roller = Curved surface of the cylinder
= 2pirh
= 2 * 22/7 * 49 * 120
= 36960 cm^2.
Therefore Area of 1 revolution = 36960 cm^2.
Area of 1000 revolutions = 36960 * 1000
= 36960000cm^2
= 36960000 * 1/100 * 1/100
= 3696m^2.
Therefore the area of the playground = 3696m^2.
Hope this helps!
Then the radius of the roller r = 98/2
= 49cm.
We know that Area of roller = Curved surface of the cylinder
= 2pirh
= 2 * 22/7 * 49 * 120
= 36960 cm^2.
Therefore Area of 1 revolution = 36960 cm^2.
Area of 1000 revolutions = 36960 * 1000
= 36960000cm^2
= 36960000 * 1/100 * 1/100
= 3696m^2.
Therefore the area of the playground = 3696m^2.
Hope this helps!
If possible brainliest it. Thanks
Similar questions