Math, asked by sreelover, 1 year ago

The diameter of a 120cm long roller is 98cm. If it takes 1000 complete revolutions to level a playground. Find the area of the playground in sq.m.

Answers

Answered by Kaira1111
1
3696 sq.m. will be the area of the playground

sreelover: can u tell me why r we multiplying 1/100 twice?
siddhartharao77: Actually 1m^2 = 10000 sqcm.(100 * 100)
Answered by siddhartharao77
6
Given Diameter of the roller d = 98cm.

Then the radius of the roller r = 98/2

                                                  = 49cm.


We know that Area of roller = Curved surface of the cylinder

                                                = 2pirh

                                                = 2 * 22/7 * 49 * 120

                                                = 36960 cm^2.


Therefore Area of 1 revolution = 36960 cm^2.

Area of 1000 revolutions = 36960 * 1000

                                           = 36960000cm^2

                                           = 36960000 * 1/100 * 1/100

                                            = 3696m^2.


Therefore the area of the playground = 3696m^2.



Hope this helps!

siddhartharao77: If possible brainliest it. Thanks
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