Math, asked by patelgovind214, 11 months ago

The diameter of a circular park is 56 m. On its outside, there is 3 m wide path, running around it. find
cost of turfing the path at 5 per square metre.

Answers

Answered by diwakarsinghblm
0

Diameter of circle=56m.

Radius of circle= diameter/2.

R=56/2.

R= 28

Around path of 3m.

Full radius of circle=28+3=31.

Volume of circle=2πr.

V.of.circle=2×22/7×31

V.of circle= 1364/7.

v.of.circle=194.8m2. with path.

V.of circle= 2πr=2×22/7×28

V.of circle=176m.

V.of .circle with path- V.of circle.

194.8-176 .

=18.8m.

Cost if path =18.8×5.

Cost of path =94 ruppee.

Answered by varunsojha2005
0

ANSWER-

Step-by-step explanation:

GIVEN DIAMETER =56 M

SO RADIUS =56/2=28

WIDE=3M

SO INNER RADIUS=r=28-3=25

AREA OF PATH=ar of outer circle-ar of inner circle

=pie r 1 sqr-pier2 sqr

22/7*(28)sqr-22/7*25 sqr

22/7*784-22/7*625

take common 22/7(784-625)

22/7(159)

rs 499.7

price5 per sqr /m2=499.7*5

2,498.5

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