Question

the diameter of a circular park is 84cm a 3.4 m wide road runs outside around it find the cost of constructing the road at rupee 20 per meter square​

Answer 1

Answer:

Radius of park x =84/2 =42 m

radius of outer circle y = 42 +3.5 =45.5m

area of road=

\pi( {y}^{2} - {x}^{2} ) \\ \pi( {45.5}^{2} - {42}^{2} ) \\ \frac{22}{7} (2070.25 - 1764) \\ \frac{22}{7} \times 306.25 \\ 962.25 {m}^{2} \\

cost of construction =20×962.25

= rs 19245

Step-by-step explanation:

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