Question

The diameter of a cylindrical roller is 9.1 cm, and is 2.8 m long. Find the area it will cover in 30 revolutions​

Answer 1

Answer:

find surface area and multiply with 30

Answer 2

Area of 30 revolution is 2402.4 cm².

Step-by-step explanation:

Given : The diameter of a cylindrical roller is 9.1 cm, and is 2.8 m long.

To Find : The area it will cover in 30 revolutions​ ?

Solution :

The diameter of a cylindrical roller is 9.1 cm.

The radius of a cylindrical roller is 4.55 cm.

The height of the cylinder is 2.8 meter long.

The area of the roller = Curved surface of cylinder

$A=2\pi r h$

$A=2\times \frac{22}{7}\times 4.55\times 2.8$

$A=80.08\ cm^2$

So, Area of 1 revolution is 80.08 cm².

Area of 30 revolution is $80.08\times 30$

Area of 30 revolution is 2402.4 cm².

#Learn more

A cylindrical road roller is 1 m long. Its inner diameter is 54 cm and thickness of the iron sheet rolled into the road roller is 9 cm. Find the weight of the roller, if 1 cm^3 iron weighs 8 gm (pi = 3.14).

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