Math, asked by nirmit5351, 1 year ago

The diameter of a garden roller is 1.4m and it is 2m long. How much are will it cover in 5 revolutions.

Answers

Answered by Dropout05
2
length covered in 5 revolutions
= circumference X no. of revolutions
= πd x 5
= (22/7)*(1.4/2)*5
= 22m

width= 2m

Area covered= length X width
=22 X 2
= 44 sq. metres._________Ans
Answered by lAnniel
4

\huge{\underline{\sf{Question :-}}}}

The diameter of a garden roller is 1.4m and it is 2m long. How much area will it cover in 5 revolutions.

\huge{\underline{\sf{Answer :-}}}}

\sf Given\begin{cases} &\sf{Diameter\;of\;the\; garden\:roller,\:D\;=\be{1.4\:m}}\\&\sf{Width\;of\;the\;garden\: roller,\:h=\;\bf{2\:m}}\end{cases}\\ \\

\boxed{ \sf \red{  To \: Find : }}

✏ Area it will cover in 5 revolutions = ❓

\green{\underline\bold{We \:know\:,}}

✏ Radius, r = \frac{Diameter}{2}

✏ r = \frac{1.4}{2}

✏ r = 0.7 m

\green{\underline\bold{From\:the\:formula,}}

\boxed{ \sf \blue{Area \: of\:the\:roller=\: Curved\:surface\:area\:of\:the\:cylinder }}

= 2Πrh

= 2 × \frac{22}{7} × 0.7 × 2

= 8.8 m sq.

\green{\underline\bold{Now,}}

\boxed{ \sf \blue{ Area\: of \:the\: roller\: it\:will\:cover\: in\: 1 \:revolution=\:area\:of\:the\:roller }}

= 8.8 m sq.

\boxed{ \sf \blue{ Area\: of \:the\: roller\: it\:will\:cover\: in\:5 \:revolutions= }}

= 8.8 × 5

= 44 m sq.

\pink{\underline\bold{∴The\:required\:answer\:is\: = \: 44\: m\: sq.}}

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