Question

the diameter of a road roller, 1m 40cm long is 80cm. if it takes 60 revolution to levelthe surface find the cost of leveling the surface at ruppe 10 per sq m

Answer 1

Answer:

diameter of roller=0.40m

length of roller=1.40m

curve surface area=πr^2h

=22/7 X 0.40 X 0.40 X 1.40

=22 X 0.40 X 0.40 X 0.20

=0.704m^2

total area covered=0.704m^2 X 60

=42.24m^2

cost=42.24 X 0.10

=Rs 4.224