Question

The diameter of a roller 120 cm long is 84 cm. If it takes 500 complete revolutions to level a play
ground, determine the cost of leveling at the rate of 30 paise per m². (use n=22/7)​

Answer 1

Answer:

47520 p/m^2

Step-by-step explanation:

diameter=84cm

therefore radius=42cm

height=120cm

area rolled in 1 revolution=c.s.a  

=2*22/7*r*h=2*22/7*42*120

316800 cm^2 = 3.168 m^2

area of field=500*3.168

=1584 m^2

cost=30 p/m^2

therefore, total cost=1584*30

47520 p/m^2

Answer 2

please find the answer attached above,

Hope it helps!