Math, asked by vishalchaudhary5169, 9 months ago

The diameter of a roller 120 cm long is 84 .if it takes 500 complete revolution to level a playground. Determine the cost of levelling it at the rate of 30 paise per sq.m?

Answers

Answered by anushkakavitake
3

Answer:

diameter= 120cm

radius=60cm

long/height=84cm

CSA of cylinder=2pie rh

2*22/7*60*84cm^2

44*60*12

720*44=

31680cm^2

area of ground=

31680cm^2=31680/10000 m^2

500 revolutions

500*31680/10000 m^2

=1584m^2

Similar questions