The diameter of a roller 120 cm long is 84 .if it takes 500 complete revolution to level a playground. Determine the cost of levelling it at the rate of 30 paise per sq.m?
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Answer:
diameter= 120cm
radius=60cm
long/height=84cm
CSA of cylinder=2pie rh
2*22/7*60*84cm^2
44*60*12
720*44=
31680cm^2
area of ground=
31680cm^2=31680/10000 m^2
500 revolutions
500*31680/10000 m^2
=1584m^2
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