Question

The diameter of a roller 120cm long is 84cm. It it takes 500

complete revolutions to level a playground, find the cost of

levelling it at the rate of 30 paise per square meter.​

Answer 1

Answer:

plz mark as brainlist

don't spam

Answer 2

hi mate ...

solution

given..The diameter of a roller 120cm long is 84cm. It it takes 500 complete revolutions to level a playground, the cost of levelling it at the rate of 30 paise per square meter.

here mate...The diameter of Roller is 84cm we know that radius is half of the diameter .

we get,the roller is 120 cm long that is

CURVED SURFACE AREA OF CYLINDRICAL ROLLER

=2πrh

=2×22/7×42×120

=2×22×6×120

=31680sq.cm .

ROLLER TAKES 500 complete revolutions to level the playground

which means that its curved surface area revolves 500 times to level playground.

so,AREA OF PLAYGROUND

=500×31680

=15840000sq.cm

=158400sqm

SO MATE THE COST OF LEVELLING 158400sqm area at the rate of 30 paise per sq.m

=158400×30

=4752000paise

WE KNOW THAT,

1₹=100paise

THEREFORE,

4752000/100

=47520₹

FINAL ANSWER:

THEREFORE,

THE COST OF LEVELLING THE PLAYGROUND IS ₹ 47520

I HOPE MATE IT HELPFULL TO YOU. THANK'S