Math, asked by robotchitee, 3 months ago

the diameter of a roller is 42cm and it lenght is 100cm. it takes 750 complete revolution moving once over to level a play ground.find the area of play ground.



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Answers

Answered by hizan18
1

Answer:

Area of ground = 400 × CSA of cylindrical roller

= 2 × pi× r×h ×400

= 2×22/7 × 21 × 100 × 400

=5280000 cm^2

=5280000/10000 m^2

= 528 m^2

Cost of levelling 105 m^2 = rs.50

so cost of leveling 1 m^2 = 50/105

So cost of leveling 528 m^2 = 50/105 × 528 = RS.25.14

Step-by-step explanation:


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